{"id":663,"date":"2022-02-14T13:30:00","date_gmt":"2022-02-14T12:30:00","guid":{"rendered":"https:\/\/technischemechanik.com\/?p=663"},"modified":"2022-02-13T10:08:11","modified_gmt":"2022-02-13T09:08:11","slug":"stangenschuss-beim-fusball-stosvorgang","status":"publish","type":"post","link":"https:\/\/technischemechanik.com\/de\/2022\/02\/14\/stangenschuss-beim-fusball-stosvorgang\/","title":{"rendered":"Stangenschuss beim Fu\u00dfball &#8211; Sto\u00dfvorgang"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Herzlich Willkommen!<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Diesmal sehen wir uns ein etwas sportlicheres Beispiel an, n\u00e4mlich den Stangenschuss beim Fu\u00dfball. Wir m\u00f6chten uns \u00fcberlegen welcher Effet dem Ball mitgegeben werden muss um ihn von der Stange ins Tor zu bekommen. <\/p>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<blockquote class=\"wp-block-quote is-layout-flow wp-block-quote-is-layout-flow\"><p>Ein Fu\u00dfball mit Masse m und Tr\u00e4gheitsmoment \u03b8s trifft mit der Geschwindigkeit v0 horizontal gegen den rauen Pfosten des Tores. Der Aufprall erfolgt dabei zentrisch unter dem Winkel \u03b1 zur Torlinie. Die Sto\u00dfziffer betr\u00e4gt \u03b5. <\/p><p>Wie gro\u00df muss der Effet, d.h. die Winkelgeschwindigkeit \u03c90 des Balls sein, damit er nach dem Aufprall \u00fcber die Torlinie geht, wenn w\u00e4hrend des Sto\u00dfes Haftung eintritt?<\/p><cite>Quelle: Aufgabe 6.10 (S. 143) aus D. Gross, W. Ehlers, P. Wriggers, Formeln und Aufgaben zur Technischen Mechanik 3, 8. Auflage, 2007 Springer, Berlin<\/cite><\/blockquote>\n\n\n\n<figure class=\"wp-block-image size-large\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"480\" height=\"482\" data-attachment-id=\"666\" data-permalink=\"https:\/\/technischemechanik.com\/de\/stoss_2017_06_14\/\" data-orig-file=\"https:\/\/i0.wp.com\/technischemechanik.com\/wp-content\/uploads\/2022\/02\/stoss_2017_06_14.jpg?fit=480%2C482&amp;ssl=1\" data-orig-size=\"480,482\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"stoss_2017_06_14\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/technischemechanik.com\/wp-content\/uploads\/2022\/02\/stoss_2017_06_14.jpg?fit=480%2C482&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/technischemechanik.com\/wp-content\/uploads\/2022\/02\/stoss_2017_06_14.jpg?resize=480%2C482&#038;ssl=1\" alt=\"\" class=\"wp-image-666\" \/><\/figure>\n<\/div><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Die Angabe gibt es wie \u00fcblich als Download inkl. Endergebnissen. Ihr k\u00f6nnt damit das Beispiel zuerst selbst rechnen und dann mit meiner Musterl\u00f6sung vergleichen. <\/p>\n\n\n\n<div data-wp-interactive=\"core\/file\" class=\"wp-block-file\"><object data-wp-bind--hidden=\"!state.hasPdfPreview\" hidden class=\"wp-block-file__embed\" data=\"https:\/\/technischemechanik.com\/wp-content\/uploads\/2022\/02\/stoss-s33.pdf\" type=\"application\/pdf\" style=\"width:100%;height:600px;\" aria-label=\"Einbettung von Einbettung von stoss-s33..\"><\/object><a id=\"wp-block-file--media-99979c07-804d-474b-abb3-f7a08ed75907\" href=\"https:\/\/technischemechanik.com\/wp-content\/uploads\/2022\/02\/stoss-s33.pdf\">stoss-s33<\/a><a href=\"https:\/\/technischemechanik.com\/wp-content\/uploads\/2022\/02\/stoss-s33.pdf\" class=\"wp-block-file__button\" download aria-describedby=\"wp-block-file--media-99979c07-804d-474b-abb3-f7a08ed75907\">Herunterladen<\/a><\/div>\n\n\n\n<p class=\"wp-block-paragraph\"> <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Wir starten dieses Beispiel auch diesmal mit einem Freik\u00f6rperbild in welches wir alle Geschwindigkeiten und Sto\u00dfantriebe einzeichnen. Daraus lassen sich Impuls- und Drehimpulssatz f\u00fcr den Ball ableiten. Zus\u00e4tzlich ben\u00f6tigen wir die Sto\u00dfhypothese und einige \u00dcberlegungen zur Kinematik w\u00e4hrend des Sto\u00dfvorganges. Aus dem damit erstellten Gleichungssystem l\u00e4sst sich dann mit wenigen Zusatz\u00fcberlegungen zur Geometrie, der ben\u00f6tigte Effet beim Schuss berechnen. Alle Schritte im Detail besprechen und berechnen wir wieder im verlinkten YouTube Video. <\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-rich is-provider-handler-einbetten wp-block-embed-handler-einbetten wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<span class=\"embed-youtube\" style=\"text-align:center; display: block;\"><iframe loading=\"lazy\" class=\"youtube-player\" width=\"712\" height=\"401\" src=\"https:\/\/www.youtube.com\/embed\/ojF1ONI6FoY?version=3&#038;rel=1&#038;showsearch=0&#038;showinfo=1&#038;iv_load_policy=1&#038;fs=1&#038;hl=de-DE&#038;autohide=2&#038;wmode=transparent\" allowfullscreen=\"true\" style=\"border:0;\" sandbox=\"allow-scripts allow-same-origin allow-popups allow-presentation allow-popups-to-escape-sandbox\"><\/iframe><\/span>\n<\/div><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Bei Fragen schreibt bitte hier oder auf YouTube einen Kommentar. Ich werde eure Fragen wie immer schnellstm\u00f6glich beantworten. <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Hat euch das Beispiel und die Erkl\u00e4rung dazu gefallen? Dann lasst bitte ein Like auf YouTube da und abonniert diesen Blog. Abonniert auch unbedingt den YouTube Kanal um kein Video mehr zu verpassen. Vielen Dank!<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Bis bald mit dem n\u00e4chsten Beispiel,<br>Markus <\/p>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-8f761849 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"crowdsignal-vote-wrapper\" data-crowdsignal-vote=\"{&quot;pollId&quot;:&quot;455b5e0c-f331-43d3-a592-cc8d4f4d6034&quot;,&quot;title&quot;:&quot;Unbenannte Abstimmung&quot;,&quot;hideBranding&quot;:false,&quot;pollStatus&quot;:&quot;open&quot;,&quot;size&quot;:&quot;medium&quot;,&quot;borderWidth&quot;:1,&quot;borderRadius&quot;:5,&quot;hideResults&quot;:false,&quot;TrpContentRestriction&quot;:{&quot;restriction_type&quot;:&quot;exclude&quot;,&quot;selected_languages&quot;:[],&quot;panel_open&quot;:true},&quot;apiPollData&quot;:{&quot;id&quot;:11043881,&quot;question&quot;:&quot;&quot;,&quot;note&quot;:&quot;&quot;,&quot;settings&quot;:{&quot;title&quot;:&quot;Unbenannte Abstimmung&quot;,&quot;after_vote&quot;:&quot;results&quot;,&quot;after_message&quot;:&quot;&quot;,&quot;randomize_answers&quot;:false,&quot;restrict_vote_repeat&quot;:false,&quot;captcha&quot;:false,&quot;multiple_choice&quot;:false,&quot;redirect_url&quot;:&quot;&quot;,&quot;close_status&quot;:&quot;open&quot;,&quot;close_after&quot;:false},&quot;answers&quot;:[{&quot;answer_text&quot;:&quot;up&quot;,&quot;id&quot;:50688337,&quot;client_id&quot;:&quot;d5667f32-027e-4631-be77-a98f311ddd25&quot;},{&quot;answer_text&quot;:&quot;down&quot;,&quot;id&quot;:50688338,&quot;client_id&quot;:&quot;65db896a-3d1c-4cf4-90e9-efbc5b828961&quot;}],&quot;source_link&quot;:&quot;https:\\\/\\\/maomech.wordpress.com&quot;,&quot;client_id&quot;:&quot;455b5e0c-f331-43d3-a592-cc8d4f4d6034&quot;}}\">\n<div data-crowdsignal-vote-item=\"{&quot;answerId&quot;:&quot;d5667f32-027e-4631-be77-a98f311ddd25&quot;,&quot;type&quot;:&quot;up&quot;,&quot;TrpContentRestriction&quot;:{&quot;restriction_type&quot;:&quot;exclude&quot;,&quot;selected_languages&quot;:[],&quot;panel_open&quot;:true}}\"><\/div>\n\n<div data-crowdsignal-vote-item=\"{&quot;answerId&quot;:&quot;65db896a-3d1c-4cf4-90e9-efbc5b828961&quot;,&quot;type&quot;:&quot;down&quot;,&quot;TrpContentRestriction&quot;:{&quot;restriction_type&quot;:&quot;exclude&quot;,&quot;selected_languages&quot;:[],&quot;panel_open&quot;:true}}\"><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"crowdsignal-applause-wrapper\" data-crowdsignal-applause=\"{&quot;pollId&quot;:&quot;c0b767e1-47b5-4dc0-a3d5-76f3bacda917&quot;,&quot;title&quot;:&quot;Unbenannter Applaus&quot;,&quot;answerId&quot;:&quot;e8a232bc-57f1-4fa4-8c99-4926af8f11b8&quot;,&quot;hideBranding&quot;:false,&quot;size&quot;:&quot;medium&quot;,&quot;pollStatus&quot;:&quot;open&quot;,&quot;TrpContentRestriction&quot;:{&quot;restriction_type&quot;:&quot;exclude&quot;,&quot;selected_languages&quot;:[],&quot;panel_open&quot;:true},&quot;apiPollData&quot;:{&quot;id&quot;:11043882,&quot;question&quot;:&quot;&quot;,&quot;note&quot;:&quot;&quot;,&quot;settings&quot;:{&quot;title&quot;:&quot;Unbenannter Applaus&quot;,&quot;after_vote&quot;:&quot;results&quot;,&quot;after_message&quot;:&quot;&quot;,&quot;randomize_answers&quot;:false,&quot;restrict_vote_repeat&quot;:false,&quot;captcha&quot;:false,&quot;multiple_choice&quot;:false,&quot;redirect_url&quot;:&quot;&quot;,&quot;close_status&quot;:&quot;open&quot;,&quot;close_after&quot;:false},&quot;answers&quot;:[{&quot;answer_text&quot;:&quot;clap&quot;,&quot;id&quot;:50688339,&quot;client_id&quot;:&quot;e8a232bc-57f1-4fa4-8c99-4926af8f11b8&quot;}],&quot;source_link&quot;:&quot;https:\\\/\\\/maomech.wordpress.com&quot;,&quot;client_id&quot;:&quot;c0b767e1-47b5-4dc0-a3d5-76f3bacda917&quot;}}\"><\/div><\/div>\n<\/div>\n\n\n<div class=\"crowdsignal-feedback-wrapper\" data-crowdsignal-feedback=\"{&quot;feedbackPlaceholder&quot;:&quot;Sag mir bitte was dir besonders gefallen hat und was ich verbessern soll! Vielen Dank!&quot;,&quot;submitText&quot;:&quot;Danke f\\u00fcr dein Feedback!&quot;,&quot;surveyId&quot;:2707661,&quot;emailPlaceholder&quot;:&quot;Deine E-Mail-Adresse&quot;,&quot;emailRequired&quot;:false,&quot;header&quot;:&quot;\\ud83d\\udc4b Hallo!&quot;,&quot;hideBranding&quot;:false,&quot;hideTriggerShadow&quot;:false,&quot;submitButtonLabel&quot;:&quot;Senden&quot;,&quot;toggleOn&quot;:&quot;click&quot;,&quot;triggerLabel&quot;:&quot;Feedback&quot;,&quot;x&quot;:&quot;left&quot;,&quot;y&quot;:&quot;bottom&quot;,&quot;status&quot;:&quot;open&quot;,&quot;emailResponses&quot;:true,&quot;TrpContentRestriction&quot;:{&quot;restriction_type&quot;:&quot;exclude&quot;,&quot;selected_languages&quot;:[],&quot;panel_open&quot;:true},&quot;nonce&quot;:&quot;77006c9619&quot;}\"><\/div>","protected":false},"excerpt":{"rendered":"<p>Herzlich Willkommen! Diesmal sehen wir uns ein etwas sportlicheres Beispiel an, n\u00e4mlich den Stangenschuss beim Fu\u00dfball. Wir m\u00f6chten uns \u00fcberlegen welcher Effet dem Ball mitgegeben werden muss um ihn von der Stange ins Tor zu bekommen. Ein Fu\u00dfball mit Masse m und Tr\u00e4gheitsmoment \u03b8s trifft mit der Geschwindigkeit v0 horizontal gegen den rauen Pfosten des &hellip; <a href=\"https:\/\/technischemechanik.com\/de\/2022\/02\/14\/stangenschuss-beim-fusball-stosvorgang\/\" class=\"more-link\"><span class=\"screen-reader-text\">Stangenschuss beim Fu\u00dfball &#8211; Sto\u00dfvorgang<\/span> weiterlesen<\/a><\/p>\n","protected":false},"author":110396568,"featured_media":352,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_coblocks_attr":"","_coblocks_dimensions":"","_coblocks_responsive_height":"","_coblocks_accordion_ie_support":"","_crdt_document":"","advanced_seo_description":"","jetpack_seo_html_title":"","jetpack_seo_noindex":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":false,"jetpack_social_options":{"image_generator_settings":{"template":"highway","default_image_id":0,"font":"","enabled":false},"version":2},"jetpack_post_was_ever_published":false},"categories":[2602546,1145536,2552358],"tags":[129538,25466,2245662,750913297,14741952,35890,350894,166867,47541,22094049,911145,569973948,4288685,122966141,1488390,947685,5685069,775366,662707,720191,1213491,9160793,10126,67765249,73726871,27746161,161115,301853,750913300,172005,2411,122145655,1121513,727213064,82782145,727213062,2326513,2121286,2722,462567],"class_list":["post-663","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-ubungsaufgaben","category-dynamik","category-stos","tag-aufgabe","tag-beispiel","tag-beschleunigung","tag-dynamik","tag-einfach-erklart","tag-featured","tag-grundlagen","tag-hochschule","tag-impact","tag-kinetische-energie","tag-klausur","tag-klausuraufgabe","tag-klausurvorbereitung","tag-koordinatentransformation","tag-kugel","tag-losung","tag-lernhilfe","tag-maschine","tag-maschinenbau","tag-mechanik","tag-nachhilfe","tag-onlinekurs","tag-physik","tag-physik-grundlagen","tag-physik-nachhilfe","tag-potentielle-energie","tag-screencast","tag-stab","tag-stos","tag-studieren","tag-studium","tag-studyhelp","tag-technische-mechanik","tag-technische-mechanik-1","tag-technische-mechanik-3","tag-technische-mechanik-2","tag-tm-1","tag-tutorium","tag-uni","tag-wiederholung"],"jetpack_publicize_connections":[],"jetpack_featured_media_url":"https:\/\/i0.wp.com\/technischemechanik.com\/wp-content\/uploads\/2021\/12\/stoss-wordpress.png?fit=512%2C512&ssl=1","jetpack_likes_enabled":true,"jetpack_sharing_enabled":true,"jetpack_shortlink":"https:\/\/wp.me\/p7UJuu-aH","jetpack-related-posts":[],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/posts\/663","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/users\/110396568"}],"replies":[{"embeddable":true,"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/comments?post=663"}],"version-history":[{"count":5,"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/posts\/663\/revisions"}],"predecessor-version":[{"id":670,"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/posts\/663\/revisions\/670"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/media\/352"}],"wp:attachment":[{"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/media?parent=663"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/categories?post=663"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/tags?post=663"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}