{"id":935,"date":"2022-05-09T17:45:00","date_gmt":"2022-05-09T15:45:00","guid":{"rendered":"https:\/\/technischemechanik.com\/?p=935"},"modified":"2022-05-09T13:43:52","modified_gmt":"2022-05-09T11:43:52","slug":"stos-zweier-quader-inkl-reibung","status":"publish","type":"post","link":"https:\/\/technischemechanik.com\/de\/2022\/05\/09\/stos-zweier-quader-inkl-reibung\/","title":{"rendered":"Sto\u00df zweier Quader inkl. Reibung"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Herzlich Willkommen!<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Wir wollen uns diesmal einen Sto\u00df zweier Quader ansehen. Bevor jedoch der Sto\u00df passiert wird einer der beiden Quader von einer Feder angesto\u00dfen und rutscht reibungsbehaftet eine schiefe Ebene hinab. Nach dem Sto\u00dfvorgang rutschen beide Quader reibungsbehaftet weiter bis sie zum Stillstand kommen. <\/p>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<blockquote class=\"wp-block-quote is-layout-flow wp-block-quote-is-layout-flow\"><p>Der Quader A mit der Masse mA wird von einer um den Federweg x vorgespannten Feder mit Federkonstante c abgesto\u00dfen und rutscht \u00fcber eine raue schiefe Ebene mit Steigungswinkel \u03b1 auf eine raue horizontale Bahn mit Reibungskoeffizient \u03bc f\u00fcr beide Fl\u00e4chen. Dort st\u00f6\u00dft der Quader A auf einen ruhenden Quader B mit der Masse mB, wobei die Sto\u00dfzahl \u03b5 betr\u00e4gt. <\/p><p>Geg.: <br>mA=100kg, mB=50kg, c=4000N\/m, x=0.3m, \u03b1=20\u00b0, \u03bc=0.2, s1=10m, s2=3m, \u03b5=0.6 <\/p><p>Ges.: <br>*Geschwindigkeit beider Quader unmittelbar nach dem Sto\u00df. <br>*Entfernung von der Sto\u00dfstelle in der die beiden Quader zur Ruhe kommen.<\/p><cite>Quelle: Aufgabe D27 (S. 339f.) aus J. Berger, Klausurentrainer Technische Mechanik, 2. Auflage, 2008 Vieweg+Teubner, Wiesbaden<\/cite><\/blockquote>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"712\" height=\"360\" data-attachment-id=\"936\" data-permalink=\"https:\/\/technischemechanik.com\/de\/2022\/05\/09\/stos-zweier-quader-inkl-reibung\/stoss\/\" data-orig-file=\"https:\/\/i0.wp.com\/technischemechanik.com\/wp-content\/uploads\/2022\/05\/stoss.jpg?fit=1052%2C532&amp;ssl=1\" data-orig-size=\"1052,532\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"stoss\" data-image-description=\"\" data-image-caption=\"\" data-medium-file=\"https:\/\/i0.wp.com\/technischemechanik.com\/wp-content\/uploads\/2022\/05\/stoss.jpg?fit=300%2C152&amp;ssl=1\" data-large-file=\"https:\/\/i0.wp.com\/technischemechanik.com\/wp-content\/uploads\/2022\/05\/stoss.jpg?fit=712%2C360&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/technischemechanik.com\/wp-content\/uploads\/2022\/05\/stoss.jpg?resize=712%2C360&#038;ssl=1\" alt=\"\" class=\"wp-image-936\" \/><\/figure>\n<\/div><\/div><\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Die Angabe gibt es nat\u00fcrlich auch als Download inkl. Endergebnissen. Ihr k\u00f6nnt damit das Beispiel zuerst selbst rechnen und dann mit meiner Musterl\u00f6sung vergleichen. <\/p>\n\n\n\n<div data-wp-interactive=\"core\/file\" class=\"wp-block-file\"><object data-wp-bind--hidden=\"!state.hasPdfPreview\" hidden class=\"wp-block-file__embed\" data=\"https:\/\/technischemechanik.com\/wp-content\/uploads\/2022\/05\/stoss-s07.pdf\" type=\"application\/pdf\" style=\"width:100%;height:600px;\" aria-label=\"Einbettung von Einbettung von stoss-s07..\"><\/object><a id=\"wp-block-file--media-4e5714be-99df-4f5e-81ca-014eebd2dbbe\" href=\"https:\/\/technischemechanik.com\/wp-content\/uploads\/2022\/05\/stoss-s07.pdf\">stoss-s07<\/a><a href=\"https:\/\/technischemechanik.com\/wp-content\/uploads\/2022\/05\/stoss-s07.pdf\" class=\"wp-block-file__button\" download aria-describedby=\"wp-block-file--media-4e5714be-99df-4f5e-81ca-014eebd2dbbe\">Herunterladen<\/a><\/div>\n\n\n\n<p class=\"wp-block-paragraph\"> <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Bevor der Sto\u00dfvorgang selbst berechnet werden kann, m\u00fcssen wir uns einerseits der Energieerhaltung (Federvorspannung) und andererseits dem Arbeitssatz (rutschen auf der reibungsbehafteten Fl\u00e4che) bedienen. Der Sto\u00dfvorgang selbst kann entweder mittels innerem Sto\u00dfantrieb (Zerlegung des Vorgangs in zwei einzelne Quader) oder f\u00fcr das Gesamtsystem berechnet werden. Wir sehen uns hier beide M\u00f6glichkeiten an und vergleichen diese. Nach dem Sto\u00dfvorgang nutzen wir abermals den Arbeitssatz um die Strecken zu berechnen, welche die beiden Quader bis zum Stillstand weiterrutschen. Die Details gibt es wie immer im Video.<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-rich is-provider-handler-einbetten wp-block-embed-handler-einbetten wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<span class=\"embed-youtube\" style=\"text-align:center; display: block;\"><iframe loading=\"lazy\" class=\"youtube-player\" width=\"712\" height=\"401\" src=\"https:\/\/www.youtube.com\/embed\/cQ6l4J6UW84?version=3&#038;rel=1&#038;showsearch=0&#038;showinfo=1&#038;iv_load_policy=1&#038;fs=1&#038;hl=de-DE&#038;autohide=2&#038;wmode=transparent\" allowfullscreen=\"true\" style=\"border:0;\" sandbox=\"allow-scripts allow-same-origin allow-popups allow-presentation allow-popups-to-escape-sandbox\"><\/iframe><\/span>\n<\/div><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Bei Fragen schreibt bitte hier oder auf YouTube einen Kommentar. Ich werde eure Fragen wie immer schnellstm\u00f6glich beantworten. <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Hat euch das Beispiel und die Erkl\u00e4rung dazu gefallen? Dann lasst bitte ein Like auf YouTube da und abonniert diesen Blog. Abonniert auch unbedingt den YouTube Kanal um kein Video mehr zu verpassen. Vielen Dank!<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Bis bald mit dem n\u00e4chsten Beispiel,<br>Markus <\/p>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-8f761849 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"crowdsignal-vote-wrapper\" data-crowdsignal-vote=\"{&quot;pollId&quot;:&quot;455b5e0c-f331-43d3-a592-cc8d4f4d6034&quot;,&quot;title&quot;:&quot;Unbenannte Abstimmung&quot;,&quot;hideBranding&quot;:false,&quot;pollStatus&quot;:&quot;open&quot;,&quot;size&quot;:&quot;medium&quot;,&quot;borderWidth&quot;:1,&quot;borderRadius&quot;:5,&quot;hideResults&quot;:false,&quot;TrpContentRestriction&quot;:{&quot;restriction_type&quot;:&quot;exclude&quot;,&quot;selected_languages&quot;:[],&quot;panel_open&quot;:true},&quot;apiPollData&quot;:{&quot;id&quot;:11110876,&quot;question&quot;:&quot;&quot;,&quot;note&quot;:&quot;&quot;,&quot;settings&quot;:{&quot;title&quot;:&quot;Unbenannte Abstimmung&quot;,&quot;after_vote&quot;:&quot;results&quot;,&quot;after_message&quot;:&quot;&quot;,&quot;randomize_answers&quot;:false,&quot;restrict_vote_repeat&quot;:false,&quot;captcha&quot;:false,&quot;multiple_choice&quot;:false,&quot;redirect_url&quot;:&quot;&quot;,&quot;close_status&quot;:&quot;open&quot;,&quot;close_after&quot;:false},&quot;answers&quot;:[{&quot;answer_text&quot;:&quot;up&quot;,&quot;id&quot;:50917053,&quot;client_id&quot;:&quot;d5667f32-027e-4631-be77-a98f311ddd25&quot;},{&quot;answer_text&quot;:&quot;down&quot;,&quot;id&quot;:50917054,&quot;client_id&quot;:&quot;65db896a-3d1c-4cf4-90e9-efbc5b828961&quot;}],&quot;source_link&quot;:&quot;https:\\\/\\\/maomech.wordpress.com&quot;,&quot;client_id&quot;:&quot;455b5e0c-f331-43d3-a592-cc8d4f4d6034&quot;}}\">\n<div data-crowdsignal-vote-item=\"{&quot;answerId&quot;:&quot;d5667f32-027e-4631-be77-a98f311ddd25&quot;,&quot;type&quot;:&quot;up&quot;,&quot;TrpContentRestriction&quot;:{&quot;restriction_type&quot;:&quot;exclude&quot;,&quot;selected_languages&quot;:[],&quot;panel_open&quot;:true}}\"><\/div>\n\n<div data-crowdsignal-vote-item=\"{&quot;answerId&quot;:&quot;65db896a-3d1c-4cf4-90e9-efbc5b828961&quot;,&quot;type&quot;:&quot;down&quot;,&quot;TrpContentRestriction&quot;:{&quot;restriction_type&quot;:&quot;exclude&quot;,&quot;selected_languages&quot;:[],&quot;panel_open&quot;:true}}\"><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"crowdsignal-applause-wrapper\" data-crowdsignal-applause=\"{&quot;pollId&quot;:&quot;c0b767e1-47b5-4dc0-a3d5-76f3bacda917&quot;,&quot;title&quot;:&quot;Unbenannter Applaus&quot;,&quot;answerId&quot;:&quot;e8a232bc-57f1-4fa4-8c99-4926af8f11b8&quot;,&quot;hideBranding&quot;:false,&quot;size&quot;:&quot;medium&quot;,&quot;pollStatus&quot;:&quot;open&quot;,&quot;TrpContentRestriction&quot;:{&quot;restriction_type&quot;:&quot;exclude&quot;,&quot;selected_languages&quot;:[],&quot;panel_open&quot;:true},&quot;apiPollData&quot;:{&quot;id&quot;:11110877,&quot;question&quot;:&quot;&quot;,&quot;note&quot;:&quot;&quot;,&quot;settings&quot;:{&quot;title&quot;:&quot;Unbenannter Applaus&quot;,&quot;after_vote&quot;:&quot;results&quot;,&quot;after_message&quot;:&quot;&quot;,&quot;randomize_answers&quot;:false,&quot;restrict_vote_repeat&quot;:false,&quot;captcha&quot;:false,&quot;multiple_choice&quot;:false,&quot;redirect_url&quot;:&quot;&quot;,&quot;close_status&quot;:&quot;open&quot;,&quot;close_after&quot;:false},&quot;answers&quot;:[{&quot;answer_text&quot;:&quot;clap&quot;,&quot;id&quot;:50917055,&quot;client_id&quot;:&quot;e8a232bc-57f1-4fa4-8c99-4926af8f11b8&quot;}],&quot;source_link&quot;:&quot;https:\\\/\\\/maomech.wordpress.com&quot;,&quot;client_id&quot;:&quot;c0b767e1-47b5-4dc0-a3d5-76f3bacda917&quot;}}\"><\/div><\/div>\n<\/div>\n\n\n<div class=\"crowdsignal-feedback-wrapper\" data-crowdsignal-feedback=\"{&quot;feedbackPlaceholder&quot;:&quot;Sag mir bitte was dir besonders gefallen hat und was ich verbessern soll! Vielen Dank!&quot;,&quot;submitText&quot;:&quot;Danke f\\u00fcr dein Feedback!&quot;,&quot;surveyId&quot;:2707661,&quot;emailPlaceholder&quot;:&quot;Deine E-Mail-Adresse&quot;,&quot;emailRequired&quot;:false,&quot;header&quot;:&quot;\\ud83d\\udc4b Hallo!&quot;,&quot;hideBranding&quot;:false,&quot;hideTriggerShadow&quot;:false,&quot;submitButtonLabel&quot;:&quot;Senden&quot;,&quot;toggleOn&quot;:&quot;click&quot;,&quot;triggerLabel&quot;:&quot;Feedback&quot;,&quot;x&quot;:&quot;left&quot;,&quot;y&quot;:&quot;bottom&quot;,&quot;status&quot;:&quot;open&quot;,&quot;emailResponses&quot;:true,&quot;TrpContentRestriction&quot;:{&quot;restriction_type&quot;:&quot;exclude&quot;,&quot;selected_languages&quot;:[],&quot;panel_open&quot;:true},&quot;nonce&quot;:&quot;1e976aaf7a&quot;}\"><\/div>","protected":false},"excerpt":{"rendered":"<p>Herzlich Willkommen! Wir wollen uns diesmal einen Sto\u00df zweier Quader ansehen. Bevor jedoch der Sto\u00df passiert wird einer der beiden Quader von einer Feder angesto\u00dfen und rutscht reibungsbehaftet eine schiefe Ebene hinab. Nach dem Sto\u00dfvorgang rutschen beide Quader reibungsbehaftet weiter bis sie zum Stillstand kommen. Der Quader A mit der Masse mA wird von einer &hellip; <a href=\"https:\/\/technischemechanik.com\/de\/2022\/05\/09\/stos-zweier-quader-inkl-reibung\/\" class=\"more-link\"><span class=\"screen-reader-text\">Sto\u00df zweier Quader inkl. Reibung<\/span> weiterlesen<\/a><\/p>\n","protected":false},"author":110396568,"featured_media":352,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_coblocks_attr":"","_coblocks_dimensions":"","_coblocks_responsive_height":"","_coblocks_accordion_ie_support":"","_crdt_document":"","advanced_seo_description":"","jetpack_seo_html_title":"","jetpack_seo_noindex":false,"jetpack_post_was_ever_published":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":false,"jetpack_social_options":{"image_generator_settings":{"template":"highway","default_image_id":0,"font":"","enabled":false},"version":2}},"categories":[2602546,1145536,2552358],"tags":[129538,25466,2245662,750913297,14741952,35890,350894,166867,47541,22094049,911145,569973948,4288685,122966141,1488390,947685,5685069,775366,662707,720191,1213491,9160793,10126,67765249,73726871,27746161,161115,301853,750913300,172005,2411,122145655,1121513,727213064,82782145,2326513,2121286,2722,462567],"class_list":["post-935","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-ubungsaufgaben","category-dynamik","category-stos","tag-aufgabe","tag-beispiel","tag-beschleunigung","tag-dynamik","tag-einfach-erklart","tag-featured","tag-grundlagen","tag-hochschule","tag-impact","tag-kinetische-energie","tag-klausur","tag-klausuraufgabe","tag-klausurvorbereitung","tag-koordinatentransformation","tag-kugel","tag-losung","tag-lernhilfe","tag-maschine","tag-maschinenbau","tag-mechanik","tag-nachhilfe","tag-onlinekurs","tag-physik","tag-physik-grundlagen","tag-physik-nachhilfe","tag-potentielle-energie","tag-screencast","tag-stab","tag-stos","tag-studieren","tag-studium","tag-studyhelp","tag-technische-mechanik","tag-technische-mechanik-1","tag-technische-mechanik-3","tag-tm-1","tag-tutorium","tag-uni","tag-wiederholung"],"jetpack_publicize_connections":[],"jetpack_featured_media_url":"https:\/\/i0.wp.com\/technischemechanik.com\/wp-content\/uploads\/2021\/12\/stoss-wordpress.png?fit=512%2C512&ssl=1","jetpack_likes_enabled":true,"jetpack_sharing_enabled":true,"jetpack_shortlink":"https:\/\/wp.me\/p7UJuu-f5","jetpack-related-posts":[],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/posts\/935","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/users\/110396568"}],"replies":[{"embeddable":true,"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/comments?post=935"}],"version-history":[{"count":2,"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/posts\/935\/revisions"}],"predecessor-version":[{"id":939,"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/posts\/935\/revisions\/939"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/media\/352"}],"wp:attachment":[{"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/media?parent=935"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/categories?post=935"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/technischemechanik.com\/de\/wp-json\/wp\/v2\/tags?post=935"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}