{"id":730,"date":"2022-03-21T17:00:00","date_gmt":"2022-03-21T16:00:00","guid":{"rendered":"https:\/\/technischemechanik.com\/?p=730"},"modified":"2022-03-21T10:01:47","modified_gmt":"2022-03-21T09:01:47","slug":"statik-reduktion-eines-3d-kraftsystems","status":"publish","type":"post","link":"https:\/\/technischemechanik.com\/en\/2022\/03\/21\/statik-reduktion-eines-3d-kraftsystems\/","title":{"rendered":"Statik &#8211; Reduktion eines 3D Kraftsystems"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Herzlich Willkommen!<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Diesmal besprechen wir, warum es hilfreich sein kann mit Vektoren bei der Berechnung von Kraftsystemen zu arbeiten.<\/p>\n\n\n\n<blockquote class=\"wp-block-quote is-layout-flow wp-block-quote-is-layout-flow\"><p>Gegeben seien laut Skizze die beiden Kr\u00e4fte F1=8N und F2=10N, sowie die Koordinaten der Punkte A(0|6|0)m, B(6|4|0)m, C(3|1|2)m. F2 zeige in die positive z-Richtung. <\/p><p>Reduziere das Kraftsystem in den Ursprung des gegebenen Koordinatensystems, d.h. berechne den resultierenden Kraftvektor R, den resultierenden Momentenvektor M_R(0) und den Betrag des Kraftvektors |R|.<\/p><\/blockquote>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"712\" height=\"488\" data-attachment-id=\"731\" data-permalink=\"https:\/\/technischemechanik.com\/en\/abb07\/\" data-orig-file=\"https:\/\/i0.wp.com\/technischemechanik.com\/wp-content\/uploads\/2022\/03\/abb07.jpg?fit=1107%2C759&amp;ssl=1\" data-orig-size=\"1107,759\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"abb07\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/i0.wp.com\/technischemechanik.com\/wp-content\/uploads\/2022\/03\/abb07.jpg?fit=712%2C488&amp;ssl=1\" src=\"https:\/\/i0.wp.com\/technischemechanik.com\/wp-content\/uploads\/2022\/03\/abb07.jpg?resize=712%2C488&#038;ssl=1\" alt=\"\" class=\"wp-image-731\" \/><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\">Wir sehen, dass zuerst die beiden Kraftvektoren F1 und F2 zu bestimmen sind. Dazu m\u00fcssen wir die jeweils relevanten Einheitsvektoren berechnen. Dann kann die resultierende Kraft als Vektorsumme von F1 und F2 und das resultierende Moment aus dem Kreuzprodukt bestimmt werden. Wie das genau funktioniert sehen wir uns im verlinkten Video an.<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-rich is-provider-handler-einbetten wp-block-embed-handler-einbetten wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<span class=\"embed-youtube\" style=\"text-align:center; display: block;\"><iframe loading=\"lazy\" class=\"youtube-player\" width=\"712\" height=\"401\" src=\"https:\/\/www.youtube.com\/embed\/ot3XA_Q1170?version=3&#038;rel=1&#038;showsearch=0&#038;showinfo=1&#038;iv_load_policy=1&#038;fs=1&#038;hl=en-GB&#038;autohide=2&#038;wmode=transparent\" allowfullscreen=\"true\" style=\"border:0;\" sandbox=\"allow-scripts allow-same-origin allow-popups allow-presentation allow-popups-to-escape-sandbox\"><\/iframe><\/span>\n<\/div><figcaption><br><\/figcaption><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Bei Fragen oder Unklarheiten lasst bitte gerne einen Kommentar hier. Ich freue mich au\u00dferdem \u00fcber Anregungen zu weiteren Inhalte und generell eure R\u00fcckmeldungen. Gebt dem Video au\u00dferdem bitte einen Daumen hoch und abonniert den YouTube Kanal. Vielen Dank f\u00fcr eure Unterst\u00fctzung!<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Bis bald,<br>Markus <\/p>\n\n\n<div class=\"crowdsignal-feedback-wrapper\" data-crowdsignal-feedback=\"{&quot;feedbackPlaceholder&quot;:&quot;Sag mir bitte was dir besonders gefallen hat und was ich verbessern soll! 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Diesmal besprechen wir, warum es hilfreich sein kann mit Vektoren bei der Berechnung von Kraftsystemen zu arbeiten. Gegeben seien laut Skizze die beiden Kr\u00e4fte F1=8N und F2=10N, sowie die Koordinaten der Punkte A(0|6|0)m, B(6|4|0)m, C(3|1|2)m. F2 zeige in die positive z-Richtung. Reduziere das Kraftsystem in den Ursprung des gegebenen Koordinatensystems, d.h. berechne den &hellip; <a href=\"https:\/\/technischemechanik.com\/en\/2022\/03\/21\/statik-reduktion-eines-3d-kraftsystems\/\" class=\"more-link\">Continue reading <span class=\"screen-reader-text\">Statik &#8211; Reduktion eines 3D Kraftsystems<\/span><\/a><\/p>","protected":false},"author":110396568,"featured_media":657,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_coblocks_attr":"","_coblocks_dimensions":"","_coblocks_responsive_height":"","_coblocks_accordion_ie_support":"","_crdt_document":"","advanced_seo_description":"","jetpack_seo_html_title":"","jetpack_seo_noindex":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":false,"jetpack_social_options":{"image_generator_settings":{"template":"highway","default_image_id":0,"font":"","enabled":false},"version":2},"jetpack_post_was_ever_published":false},"categories":[2602546,2820248,172484],"tags":[25466,729611524,100678,414019,35890,5167337,750913306,727961753,350894,166867,113216,290680250,163250810,2517859,8207,662707,720191,1213491,143003,10126,73726871,750913302,161115,750913295,2411,1121513,727213064,729611525,2326513,2722,1268153,271082537,727961757,729611523],"class_list":["post-730","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-ubungsaufgaben","category-reduktion","category-statik","tag-beispiel","tag-ebenes-zentrales-kraftesystem","tag-einfuhrung","tag-erklart","tag-featured","tag-festigkeitslehre","tag-freikorperbild","tag-gleichgewicht","tag-grundlagen","tag-hochschule","tag-kraft","tag-kraftsystem","tag-kraftvektor","tag-krafte","tag-lernen","tag-maschinenbau","tag-mechanik","tag-nachhilfe","tag-newton","tag-physik","tag-physik-nachhilfe","tag-reduktion","tag-screencast","tag-statik","tag-studium","tag-technische-mechanik","tag-technische-mechanik-1","tag-technische-mechanik-grundlagen","tag-tm-1","tag-uni","tag-verstehen","tag-zentrales-kraftsystem","tag-zentrales-kraftesystem","tag-zentralkraftsystem"],"jetpack_publicize_connections":[],"jetpack_featured_media_url":"https:\/\/i0.wp.com\/technischemechanik.com\/wp-content\/uploads\/2022\/02\/reduktion-wordpress.png?fit=512%2C512&ssl=1","jetpack_likes_enabled":true,"jetpack_sharing_enabled":true,"jetpack_shortlink":"https:\/\/wp.me\/p7UJuu-bM","jetpack-related-posts":[],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/technischemechanik.com\/en\/wp-json\/wp\/v2\/posts\/730","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/technischemechanik.com\/en\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/technischemechanik.com\/en\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/technischemechanik.com\/en\/wp-json\/wp\/v2\/users\/110396568"}],"replies":[{"embeddable":true,"href":"https:\/\/technischemechanik.com\/en\/wp-json\/wp\/v2\/comments?post=730"}],"version-history":[{"count":4,"href":"https:\/\/technischemechanik.com\/en\/wp-json\/wp\/v2\/posts\/730\/revisions"}],"predecessor-version":[{"id":735,"href":"https:\/\/technischemechanik.com\/en\/wp-json\/wp\/v2\/posts\/730\/revisions\/735"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/technischemechanik.com\/en\/wp-json\/wp\/v2\/media\/657"}],"wp:attachment":[{"href":"https:\/\/technischemechanik.com\/en\/wp-json\/wp\/v2\/media?parent=730"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/technischemechanik.com\/en\/wp-json\/wp\/v2\/categories?post=730"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/technischemechanik.com\/en\/wp-json\/wp\/v2\/tags?post=730"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}